Answer:
[tex]v_i=4.12\ m/s[/tex]
Explanation:
Given that,
Final velocity, [tex]v_f=0\ m/s[/tex]
Acceleration, [tex]a=-9.8\ m/s^2[/tex]
Displacement, [tex]\Delta x = 0.87\ m[/tex]
We need to find the initial velocity of the large hopper.
Using the third equation of motion as follows :
[tex]v_f^2=v_i^2+2a\Delta x\\\\0=v_i^2+2\times (-9.8)\times 0.87\\\\v_i^2-17.052=0\\\\v_i=4.12\ m/s[/tex]
So, the initial velocity of the large hopper is 4.12 m/s.
