Respuesta :
Step-by-step explanation:
When t = 2,
h(2) = 8 + 40.8(2) - 16(2)² = 8 + 81.6 - 64 = 25.6
Therefore the height after 2 sec is 25.6.
Answer:
[tex]h(t) = 8 + 40.8t - {16t}^{2} \\ h(2) = 8 + 40.8(2) - 16 {(2)}^{2} \\ = 8+81.6 - 64 \\ = 89.6 - 64 = \boxed{25.6}[/tex]
After 2 seconds the ball will be at the height of 25.6 unit.