Answer:
The crate should be released 3,080 m in front of the target
Explanation:
Horizontal Launch
When an object is thrown horizontally with a speed v from a height of h, it describes a curved path ruled by gravity until it hits the ground.
The range or maximum horizontal distance traveled by the object can be calculated as follows:
[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]
The airplane drops a crate horizontally from a height of h= 2,750 m when flying at v=130 m/s. The range or maximum horizontal distance the crate reaches is:
[tex]\displaystyle d=130\cdot\sqrt{\frac {2*2,750}{9.8}}[/tex]
Operating:
[tex]\displaystyle d=130\cdot\sqrt{561.2245}[/tex]
d = 3,080 m
The crate should be released 3,080 m in front of the target
