Answer:
When y=32, x=16.5
Step-by-step explanation:
Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4.
We are given:
x varies inversely with y
We can write it as: [tex]x\:\alpha \:\frac{1}{y}[/tex]
[tex]x=\frac{k}{y}[/tex]
We have x = 132, when y=4
We can find value of k by using these values
[tex]x=\frac{k}{y}\\132=\frac{k}{4}\\k=132*4\\k=528[/tex]
We need to find x when y=32
[tex]x=\frac{k}{y}\\x=\frac{528}{32}\\x=16.5[/tex]
So, when y=32, x=16.5
