Answer: [tex]5x^2y^5[/tex]
Step-by-step explanation:
Given: Area of rectangle = [tex]35x^4y^{10}[/tex] square feet
Length of rectangle= [tex]7x^2y^5[/tex]
We know that,
Width of rectangle = [tex]\dfrac{\text{Area of rectangle}}{\text{Length}}[/tex]
Then,
Expression of width= [tex]\dfrac{35x^4y^{10}}{7x^2y^5}[/tex]
[tex]=\dfrac{5x^{4-2}y^{10-5}}{1}\ \ \ \ [\frac{x^m}{x^n}=x^{m=n}]\\\\=5x^2y^5[/tex]
Hence, the expression for width of the rectangle = [tex]5x^2y^5[/tex]
