Answer:
[tex]M=0.638M[/tex]
Explanation:
Hello!
In this case, since the molarity of a solution is calculated by diving the moles of solute by the volume of solution in liters, we first compute the moles of barium hydroxide in 35.5 g as shown below:
[tex]n=35.5g Ba(OH)_2*\frac{1molBa(OH)_2}{171.34gBa(OH)_2}\\\\n=0.207mol[/tex]
Then, the liters of solution:
[tex]V=325mL*\frac{1L}{1000mL} =0.325L[/tex]
Finally, the molarity turns out:
[tex]M=\frac{0.207mol}{0.325L}\\\\M=0.638M[/tex]
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