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Answer: The precipitate formed will be of calcium hydroxide.

Explanation:

When potassium hydroxide reacts with copper nitrate, a pale greenish blue precipitate of copper hydroxide is formed along with the formation of potassium nitrate.

This reaction is a type of precipitation reaction because a precipitate is being formed.

The equation for the reaction between the two follows:

[tex] 2KOH(aq.)+Cu(NO_3)_2(aq.)\rightarrow 2KNO_3(aq.)+Cu(OH)_2(s)[/tex]

By Stoichiometry of the reaction:

2 moles of potassium hydroxide reacts with 1 mole of copper nitrate to produce 2 moles of potassium nitrate and 1 mole of copper hydroxide.

The precipitate that is formed when KOH and  [tex]{\mathbf{Cu}}{\left({{\mathbf{N}}{{\mathbf{O}}_{\mathbf{3}}}}\right)_{\mathbf{2}}}[/tex] are mixed is [tex]\boxed{{\text{Cu}}{{\left({{\text{OH}}}\right)}_2}}[/tex]

Further Explanation:

Precipitation reaction:

It is the type of reaction in which an insoluble salt is formed by the combination of two solutions containing soluble salts. That insoluble salt is known as precipitate and therefore such reactions are named precipitation reactions. An example of precipitation reaction is,

[tex]{\text{AgN}}{{\text{O}}_3}\left({aq}\right)+{\text{KBr}}\left({aq}\right)\to {\text{AgBr}}\left(s\right)+{\text{KN}}{{\text{O}}_3}\left({aq}\right)[/tex]

Here, AgBr is a precipitate.

The solubility rules to determine the solubility of the compound are as follows:

1. The common compounds of group 1A are soluble.

2. All the common compounds of ammonium ion and all acetates, chlorides, nitrates, bromides, iodides, and perchlorates are soluble in nature. Only the chlorides, bromides, and iodides of [tex]{\text{A}}{{\text{g}}^ + }[/tex] , [tex]{\text{P}}{{\text{b}}^{2 + }}[/tex] , [tex]{\text{C}}{{\text{u}}^ + }[/tex] and  [tex]{\text{Hg}}_2^{2 + }[/tex] are not soluble.

3. All common fluorides, except for [tex]{\text{Pb}}{{\text{F}}_{\text{2}}}[/tex] and group 2A fluorides, are soluble. Moreover, sulfates except [tex]{\text{CaS}}{{\text{O}}_{\text{4}}}[/tex] , [tex]{\text{SrS}}{{\text{O}}_{\text{4}}}[/tex] , [tex]{\text{BaS}}{{\text{O}}_{\text{4}}}[/tex] , [tex]{\text{A}}{{\text{g}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}[/tex] and [tex]{\text{PbS}}{{\text{O}}_{\text{4}}}[/tex] are soluble.

4. All common metal hydroxides except [tex]{\text{Ca}}{\left({{\text{OH}}}\right)_{\text{2}}}[/tex] , [tex]{\text{Sr}}{\left({{\text{OH}}}\right)_{\text{2}}}[/tex] , [tex]{\text{Ba}}{\left({{\text{OH}}}\right)_{\text{2}}}[/tex]  and hydroxides of group 1A and that of transition metals are insoluble in nature.

5. All carbonates and phosphates, except those formed by group 1A and ammonium ion, are insoluble.

6. All sulfides, except those formed by group 1A, 2A, and ammonium ion are insoluble.

7. Salts that contain [tex]{\text{C}}{{\text{l}}^ - }[/tex] , [tex]{\text{B}}{{\text{r}}^ - }[/tex]  or [tex]{{\text{I}}^ - }[/tex] are usually soluble except for the halide salts of [tex]{\text{A}}{{\text{g}}^ + }[/tex] , [tex]{\text{P}}{{\text{b}}^{2 + }}[/tex]  and [tex]{\left({{\text{H}}{{\text{g}}_2}}\right)^{{\text{2 + }}}}[/tex] .

8. The chlorides, bromides, and iodides of all the metals are soluble in water, except for silver, lead, and mercury (II). Mercury (II) iodide is water insoluble. Lead halides are soluble in hot water.

9. The perchlorates of group 1A and group 2A are soluble in nature.

The given reaction occurs as follows:

[tex]2{\text{KOH}}\left( {aq}\right)+{\text{Cu}}{\left({{\text{N}}{{\text{O}}_{\text{3}}}} \right)_2}\left({aq}\right)\to2{\text{KN}}{{\text{O}}_3}\left({aq}\right)+{\text{Cu}}{\left( {{\text{OH}}}\right)_2}\left( s\right)[/tex]

This is an example of a double displacement reaction in which two ionic compounds are exchanged with each other and two new compounds are formed.   is a soluble salt and  is insoluble in nature according to the solubility rules. So [tex]{\mathbf{Cu}}{\left({{\mathbf{OH}}}\right)_{\mathbf{2}}}[/tex]  will form precipitate in this reaction.

Learn more:

1. Balanced chemical equation https://brainly.com/question/1405182

2. Net ionic equation for the reaction of [tex]{\text{MgS}}{{\text{O}}_{\text{4}}}[/tex]  with [tex]{\text{Sr}}{\left({{\text{N}}{{\text{O}}_3}}\right)_2}[/tex] : https://brainly.com/question/4357519

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: precipitation reaction, precipitate, insoluble, soluble, KNO3, Cu(OH)2, KOH, double displacement, salt, solubility rules.