Respuesta :
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At 25 C and 1 atm pressure (the standard state): P is a solid, O2 is a gas, and Cl2 is a gas.
P(s) + O2(g) + Cl2(g) ==> POCl3(l)
To make 1 mole of POCl3, we need to start with 1 mole of P, 1/2 mole of O2, and 3/2 mole of Cl2.
P(s) + 1/2O2(g) + 3/2Cl2(g) ==> POCl3(l)
NOTE: Some people write P as P4(s), in which case you would need 1/4 mole P4.
At 25 C and 1 atm pressure (the standard state): P is a solid, O2 is a gas, and Cl2 is a gas.
P(s) + O2(g) + Cl2(g) ==> POCl3(l)
To make 1 mole of POCl3, we need to start with 1 mole of P, 1/2 mole of O2, and 3/2 mole of Cl2.
P(s) + 1/2O2(g) + 3/2Cl2(g) ==> POCl3(l)
NOTE: Some people write P as P4(s), in which case you would need 1/4 mole P4.
Answer:
Explanation:
First off, it's important to identify the constituent elements of the Compound.
From the compound, we can identify the following elements;
Phosphorus (P), Oxygen (O) and Chlorine (Cl)
So we have;
P + O + Cl --> POCl3
The standard states of elements are the phases that they adopt at a Temperature of 25°C and Pressure of 1 atm.
For POCl3, the standard form of P is P4 (s) while O2 (g) for O and Cl2 (g) for Cl. With this, we now have;
P4 + O2 + Cl2 --> POCl3
Upon balancing, we have;
P4 + 2O2 + 6Cl2 --> 4POCl3
The above equation shows 4 moles of POCl3, since the question stated one mole, we now have;
1/4 P₄ (s) + 1/2 O₂(g) + 3/2 Cl₂ (g) -----> POCl₃ (l)
