let T1 and T2 be tension in ropes1 and 2 respectively. since system is stationary (equilibrium), considering both ropes + beam as a system
for horizontal equilibrium (no movement in that direction, so resultant force must be zero horizontally) T1sin(20) = T2sin(30) => T1 = T2sin(30) / sin(20)
for vertical equilibrium, (no movement in this direction, so resultant force must be zero vertically) T1cos(20) + T2cos(30) = mg
m = 900kg, substituting for T1 T2sin(30)*cos(20)/sin(20) + T2cos(30) = 900g 2.328*T2 = 900*9.8 T2 = 3788.65N so T1 from (1) T1 = 5535.21N
