Respuesta :
p(z < x) = 0.6064 - 0.5 = 0.1064
From the normal distribution table
P(z < 0.27) = 0.1064
Therefore the z-score is 0.27
I can't explain it very well for you, sorry.
From the normal distribution table
P(z < 0.27) = 0.1064
Therefore the z-score is 0.27
I can't explain it very well for you, sorry.
z = invNorm(.6064) = .2699 0r .27 (to the nearest hundredth)
z = .27
Area to the left of the Green Line(where z = .27) is 60.64% of the Area under the standard Normal Curve.
