The mass of lead = 22,939 kg
Further explanation
Given
mass alcohol=1600 kg
The density of lead =11300kg\m³ and density of alcohol=790kg\m³
Required
mass of lead
Solution
[tex]\tt V=\dfrac{mass}{\rho}\\\\V=\dfrac{1600}{790}\\\\V=2.03~m^3[/tex]
the volume of lead=volume of alcohol=2.03 m, so the mass of lead :
[tex]\tt m=\rho\times V\\\\m=11300\times 2.03\\\\m=22,939~kg[/tex]
