Answer:
0.33%
Explanation:
So, from the question it is given that the mass of the hydrogen peroxide in percentage is = 3% that is to say there are 3.0grams of hydrogen peroxide in 100mL of water. Therefore, the number of moles of hydrogen peroxide = 3/ molar mass = 3/ 34.02 = 0.088 moles.
Also, the mass of hydrogen peroxide = number of moles × molar mass = 0.088 × 34.02 = 2.99grams. Hence, the percentage by mass = [2.99/100 mL 0f water] × 100 = 2.99%
Therefore, the error in percentage = [ (3 - 2.99)/3 ]% × 100 = 0.33%
The percent error in the calculation has been 0.34%.
The moles of Hydrogen peroxide in 3% solution has been:
3% solution = 3 grams in 100 ml.
The molecular mass of hydrogen peroxide = 34.02 g/mol
The moles of hydrogen peroxide can be given as:
1 mole = 34.02 g/mol
3 g/100 ml = 0.088 mol.
The moles of hydrogen peroxide has been 0.088 mol.
Mass of hydrogen peroxide in 0.088 mol has been:
Mass = Moles × molecular mass
Mass of hydrogen peroxide = 0.088 × 34.02
Mass of hydrogen peroxide = 2.99 grams.
% of hydrogen peroxide = 2.99%.
The error in the calculation can be given as:
Error = [tex]\rm \dfrac{Bottle\;-\;Experimental}{Bottle}\;\times\;100[/tex]
Error = [tex]\rm \dfrac{3-2.99}{3}\;\times\;100[/tex]
Error = 0.34%.
The percent error in the calculation has been 0.34%.
For more information about the errors, refer to the link:
https://brainly.com/question/3105259
