Answer:
134.5 degree
Step-by-step explanation:
first find the remaining side of a triangle
BY using cosine rule
C^2=A^2+B^2-2ABcosx
apply square root both sides
√c^2 =√[4^2+10^2-2(4)(10)cos29]
C=√(116-69.96958)
C=√46.03
C=6.8
Now find angle using cosine rule
C^2=A^2+B^2-2ABcosx
10^2=4^2+6.78^2-2(4)(6.78)cosx
100=16+45.9684-54.24cosx
100=61.9684-54.24cosx
100-61.9684=-54.24cosx
(38.0316)/-54.24=(-54.4cosx)/-54.24
-0.70117=cosx
X= cos inverse of -0.70117
x=134.5 degree
