Mass of ammonia produced : 121.38 g
Further explanation
Given
Reaction
3H₂(g) + N₂(g) ⇒ 2NH₃(g)
100g of N₂
Required
Ammonia produced
Solution
mol of N₂ :
[tex]\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{100}{28}\\\\mol=3.57[/tex]
From the equation, mol ratio of N₂ and NH₃ = 1 : 2, so mol NH₃ :
[tex]\tt \dfrac{2}{1}\times 3.57=7.14~moles[/tex]
mass of NH₃(MW=17 g/mol) :
[tex]\tt mass=mol\times MW\\\\mass=7.14\times 17\\\\mass=121.38~g[/tex]
