Answer:
[tex]\frac{tanA}{1+secA} = tan (\frac{A}{2} )[/tex]
Explanation:
Given
= [tex]\frac{tanA}{1+secA}[/tex]
[tex]= \frac{\frac{sinA}{cosA} }{\frac{1+cosA}{cosA} }[/tex]
= [tex]\frac{sinA}{1+cosA} = \frac{2sin\frac{A}{2} cos\frac{A}{2} }{2cos^{2} \frac{A}{2} }[/tex]
[tex]= tan\frac{A}{2}[/tex]
