Time required : 132.2 s
Further explanation
Given
mass of Silver = 0.37 g
current = 2.5 A
Required
time do deposit
Solution
Faraday's Law :
[tex]\tt W=\dfrac{e.i.t}{96500}[/tex]
e = ar/valence (valence Ag = 1)
i = current
t = time = s
[tex]\tt 0.37~g=\dfrac{108/1\times 2.5~A\times t }{96500}\\\\t=132.2~s[/tex]
