−1
C
−1
and L
f
=3.5×10
5
Jkg
−1
Mass of copper block m=2kg
Heat released by the copper block is equal to the heat gained by the ice to melt.
Let the mass of the ice melted be M.
Change in temperature of copper block ΔT=500−0=500
o
C
∴ mS(ΔT)=ML
f
Or 2×400×500=M×3.5×10
5
⟹ M=1.14kg
