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A 23.0 kg child is riding a playground merry-go-round that is rotating at 30.0 rpm. What centripetal force, in N, must she exert to stay on if she is 2.00 m from its center

Respuesta :

Answer:

The value is  [tex]F = 454 \ N[/tex]

Explanation:

From the question we are told that

   The mass of the child is  [tex]m = 23.0 \ kg[/tex]

   The angular velocity is  [tex]w = 30 \ rpm = \frac{2 \pi * 30 }{60} = 3.142 \ rad/s[/tex]

   The distance from the center is  [tex]r = 2.0 \ m[/tex]

Generally the centripetal force is mathematically represented as

       [tex]F = m * w^2 * r[/tex]

=>   [tex]F = 23 * 3.142 ^2 * 2[/tex]    

=>   [tex]F = 454 \ N[/tex]