Answer:
the velocity of the pin after the collision is 2.7 m/s
Explanation:
The computation of the velocity of the pin after the collusion is as follows:
Given that
Mass of the ball = M = 7.3 kg
Mass of pin = m = 1.6 kg
The Velocity of the ball prior collision = U = 6 m/ s
The Velocity of the pin prior collision= u =0
The Velocity of the ball after collision = V = 5.4 m/s
Based on the above information
As we know that
Here the conservation law respect to the linear momentum is applied
mu+ MU = mv + MV
0 + 43.8 = 1.6 v + 39.42
1.6 v = 4.38
v = 2.7 m/s
Hence, the velocity of the pin after the collision is 2.7 m/s
The final velocity of the pin after the collision is 2.7 m/s.
The given parameters:
The final velocity of the pin after the collision is determined by applying the principle of conservation of linear momentum;
[tex]m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2\\\\ 7.3(6) + 1.6(0) = 7.3(5.4) + 1.6(v_2)\\\\ 43.8 = 39.42 + 1.6v_2\\\\ 1.62v_2 = 4.38\\\\ v_2 = \frac{4.38}{1.62} \\\\ v_2 = 2.7 \ m/s[/tex]
Thus, the final velocity of the pin after the collision is 2.7 m/s.
Learn more about conservation of linear momentum here: https://brainly.com/question/7538238
