Complete Question
A certain 50 cm spring will stretch (in cm) one fifth the weight (in kg) attached to it. How long will the spring be if a 35 kg weight is attached to it
Answer:
The value is [tex]L_w = 57 \ cm[/tex]
Step-by-step explanation:
The length of the spring is [tex]L = 50 \ cm = 0.5 \ m[/tex]
The mass attached to it is [tex]w = 35 \ kg[/tex]
Generally given from that the spring will stretch one fifth of the weight (in kg)attached to it , it then means that the new length of the spring whenever a weight is attached to it is mathematically represented as
[tex]L_w = L + \frac{W}{5}[/tex]
=> [tex]L_w = 50 + \frac{35}{5}[/tex]
=> [tex]L_w = 57 \ cm[/tex]
