Answer:
(C). {3}
Step-by-step explanation:
[tex]\frac{x}{2(x+1)}[/tex] = [tex]\frac{-2x}{4(x+1)}[/tex] + [tex]\frac{2x-3}{x+1}[/tex] ( x ≠ - 1 )
[tex]\frac{x}{2(x+1)}[/tex] - [tex]\frac{2x-3}{x+1}[/tex] + [tex]\frac{x}{2(x+1)}[/tex] = 0
[tex]\frac{2x-3}{x+1}[/tex] - [tex]\frac{x}{(x+1)}[/tex] = 0
[tex]\frac{x-3}{x+1}[/tex] = 0 ⇒ x = 3
