Answer:
[tex]\sin(C)=\pm\sqrt{1-\cos^2(C)}[/tex]
Step-by-step explanation:
Given the Pythagorean Identity:
[tex]\sin^2(C)+\cos^2(C)=1\\[/tex]
We want to solve for sin(C).
First, we will subtract cos²(C) from both sides:
[tex]\sin^2(C)=1-\cos^2(C)[/tex]
Next, we will take the square root of both sides. Since we are taking an even-root, we will need to add plus/minus. Hence:
[tex]\sin(C)=\pm\sqrt{1-\cos^2(C)}[/tex]
