Answer:
Lower Limit = 2m-L
Step-by-step explanation:
Given that,
The mid value of class = m
Upper limit in the frequency table = L
We need to find the lower limit of the class.
The mid value of a class is given by :
[tex]\text{mid-value}=\dfrac{\text{lower limit + upper limit}}{2}\\\\m=\dfrac{L+\text{lower limit}}{2}\\\\2m=L+\text{lower limit}\\\\\text{lower limit}=2m-L[/tex]
Hence, the lower limit of the class is 2m-L.
