Answer:
D
Step-by-step explanation:
[tex]\frac{x}{4}\leq \frac{9}{x} \\x\leq \frac{36}{x} \\let x<0\\x^2\geq 36\\|x|\geq 6\\x\leq -6~and ~x\geq 6\\but~x<0\\so~x\leq -6\\again~let~x> 0\\\\x\neq ~0\\x^2\leq 36\\|x|\leq 6\\-6\leq x\leq 6\\as~x>0\\so~0< x\leq 6[/tex]
combininig the two cases
x≤-6 and 0<x≤6
