Help!!

A 30-N force is applied to a 4-kg object to move it with a constant

velocity of 2 m/s across a level surface. The coefficient of friction

between the object and the surface is approximately (Use the

approximation: g - 10 m/s/s.)


A 0.20

B O 0.50

C 0.55

D 0.75

Respuesta :

Answer:

[tex]\mu=0.75[/tex]

Explanation:

Given that,

Force acting on an object, F = 30 N

Mass of the object, m = 4 kg

It is moving with a constant velocity of 2 m/s across a level surface.

We need to find the coefficient of friction  between the object and the surface. Let it is μ. Force in terms of coefficient of friction  is given by :

F = μ N, Where N is normal force, N = mg

[tex]\mu=\dfrac{F}{mg}\\\\\mu=\dfrac{30}{4\times 10}\\\\\mu=0.75[/tex]

So, the coefficient of friction  between the object and the surface is 0.75.