Answer:
7 * 10^-4Wb
Explanation:
The magnetic flux is the product of the inductance and current
Magnetic flux = LI
L is the inductance = 3.5mH
I is the current = 2.0A
Number of turns N = 2A
Since for a 10-turn solenoid, L = 3.5mH
For a one-turn solenoid, L = 3.5/10 = 0.35mH
magnetic flux = 0.35mH * 2
magnetic flux = 0.35 * 10^-3 * 2
magnetic flux = 0.7* 10^-3
Magnetic flux = 7 * 10^-4Wb
Hence the magnetic flux through each turn is 7 * 10^-4Wb
The magnetic flux through each turn is 7 ×10⁻⁴ Wb. The magnetic flux is the product of the inductance and current.
The surface integral of the normal component of the magnetic field B across a surface is the magnetic flux through that surface. It is commonly indicated by the letters B.
The weber is the SI unit for magnetic flux, while the maxwell is the CGS unit.
The given data in the problem is;
[tex]\rm \phi[/tex] is the magnetic flux =?
L is the inductance = 3.5mH
I is the current = 2.0A
N number of turns of solenoid = 2A
The inductance for the one turn is found by;
For a 10-turn solenoid, L = 3.5mH
For a one-turn solenoid, L = 3.5/10 = 0.35mH
The megnetic flux through each turn is found by;
[tex]\rm \phi = L \times I \\\\ \rm \phi = 0.35 \times 10^{-3}\times 2\\\\ \rm \phi =7 \times 10^{-4}[/tex]
Hence the magnetic flux through each turn is 7 ×10⁻⁴ Wb.
To learn more about the megnetic flux refer to the link;
https://brainly.com/question/13290530
