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A force of 10 newtons toward the right is exerted on a

wooden crate initially moving to the right on a horizontal

wooden floor. The crate weighs 25 newtons.


1. Calculate the magnitude of the force of friction between the crate and the floor.


2. What is the magnitude of the net force acting on the crate?

Respuesta :

Answer:

Explanation:

coefficient of kinetic friction of wooden floor μ = .4

force of friction = μ R , R is reaction force of floor

R = mg = weight of body

R = 25 N

force of friction = .4 x 25 = 10 N

Net force on the crate = 10 - 10 = zero .

Net force on the body will be nil.

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