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A skateboarder skates down a ramp for 3 seconds. If his initial velocity was 0.8 m/s and · his final velocity was 7 m/s, what was his acceleration?

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onyebuchinnaji

Answer:

The acceleration of the skateboarder is 2.067 m/s²

Explanation:

Given;

initial velocity of the  skateboarder, u = 0.8 m/s

final velocity of the  skateboarder, v = 7 m/s

time of motion, t = 3 s

The acceleration of the skateboarder is given as;

[tex]a = \frac{v-u}{t}\\\\a = \frac{7-0.8}{3}\\\\a = 2.067 \ m/s^2[/tex]

Therefore, the acceleration of the skateboarder is 2.067 m/s²

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