The sum of three times a Number (x) and (15) is equal to 42.
The numbers.
The first no. will be [tex]\sf{3x(3×x=3x)}[/tex]
And,the second no. will be [tex]\bf{15}[/tex]
[tex]\implies\sf{3x+15=42}[/tex]
[tex]\implies\sf{3x=42-15}[/tex]
[tex]\implies\sf{3x=27}[/tex]
[tex]\implies\sf{x=}\dfrac{27}{3}[/tex]
[tex]\implies\sf{x=9}[/tex]
Therefore,the first number will be ,
[tex]\leadsto{3x=3×9=27}[/tex]
[tex]\bf\underline\green{Verification:-}[/tex]
[tex]\leadsto\bf{27+15=42}[/tex]
[tex]\leadsto\bf{42=42}[/tex]
Hence,Verified.
Answer:
3Yx15=42
3yx15+=42
-15 -15
3y=27
3/3=27/3
y=9
Step-by-step explanation:
