5ml of mixture of CH4 and C2H4 need 13.2 ml of oxygen for complete combustion.calculate the volume of each gas in the mixture based on the law of gaseous volume.​

Respuesta :

Answer:

Explanation:

CH₄ + 2O₂ = CO₂ + 2H₂O

C₂H₄ + 3O₂ = 2CO₂ + 2H₂O

Let volume of CH₄ be V , so volume of C₂H₄ will be 5 - V

CH₄    +    2O₂   =    CO₂   +   2H₂O

1 vol           2 vol

V                2 V

V vol of CH₄   will require 2 V of O₂

C₂H₄     +    3O₂    =    2CO₂   +   2H₂O

5 - V       3( 5 - V )

5 - V vol of C₂H₄ will require 3 ( 5 - V ) vol of oxygen .

Total oxygen required = 2 V + 3 ( 5 - V )

2 V + 3 ( 5 - V ) = 13.2

2 V + 15 - 3V = 13.2

V = 1.8 ml

vol of CH₄ = 1.8

vol of C₂H₄ = 5 - 1.8 = 3.2 ml.