If k(x) = x^2 and p(x) = k(x) + n, what is the value of n?
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Answer:
The value of n is -6
Step-by-step explanation:
∵ k(x) = x²
→ Its graph is a parabola with vertex (0, 0)
∴ The vertex of the prabola which represents it is (0, 0)
∵ The given graph is the graph of p(x)
∵ Its vertex is (0, -6)
∴ h = 0 and k = -6
∵ a = 1
→ Substitute them in the form above
∴ p(x) = 1(x - 0)² + -6
∴ p(x) = x² - 6
→ Substitute x² by k(x)
∴ p(x) = k(x) - 6
∵ p(x) = k(x) + n
→ By comparing the two right sides
∴ n = -6
∴ The value of n is -6
Look at the attached figure for more understanding
The red parabola represents k(x)
The blue parabola represents p(x)
The value of the n is -6.
y = a(x-h)2 + k
where,
(h, k) are the coordinates of the vertex of the parabola in form (x, y);
a defines how narrower is the parabola, and the "-" or "+" that the parabola will open up or down.
k(x) = x^2
p(x) = k(x) + n
p(x) = k(x)+n
p(x) = x² + n
Comparing with the Equation of a parabola,
y = a(x-h)2 + k
p(x) = x² + n
Therefore, the value of n is k which is the y coordinate of the vertex of the parabola.
Looking at the coordinates of the vertex of the parabola,
(h, n) = (0, -6)
Hence, the value of the n is -6.
Learn more about Parabola:
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