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At Joe's Pizzeria, small pizzas cost $7.50, and large pizzas cost
$11.00. One day between 3:00 PM and 9:00 PM, Joe sold 100 pizzas
and took in $848. How many more small pizzas than large pizzas did
Joe sell during that 6-hour period?
(A) 28
(B) 44
(C) 56
(D) 72

Respuesta :

absor201

Answer:

Option B. 44 is the correct answer

Step-by-step explanation:

Let l be the number of large pizzas and s be the number of small pizzas

Then according to the given statement the equations will be:

[tex]l+s = 100\ \ \ Eqn\ 1\\11l+7.5s = 848\ \ \ Eqn\ 2[/tex]

From equation 1

[tex]l = 100-s[/tex]

Putting in equation 2

[tex]11(100-s)+7.5s = 848\\1100-11s+7.5s = 848\\-3.5s+1100 = 848\\-3.5s = 848-1100\\-3.5s = -252\\\frac{-3.5s}{-3.5} = \frac{-252}{-3.5}\\s = 72[/tex]

Putting s=72 in equation 1

[tex]l+72 = 100\\l = 100-72\\l = 28[/tex]

How many more small pizzas means we have to find s-l

So,

s-l = 72-28 = 44

Hence,

Option B. 44 is the correct answer

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