Given:
Five less than three-fourths of an integer is the same as five more than one-eighth of the same integer.
To find:
The integer.
Solution:
Let x be the unknown integer.
So, according to the question,
[tex]\dfrac{3}{4}x-5=5+\dfrac{1}{8}x[/tex]
[tex]\dfrac{3}{4}x-\dfrac{1}{8}x=5+5[/tex]
[tex]\dfrac{6x-x}{8}x=10[/tex]
Multiply both sides by 8.
[tex]5x=10\times 8[/tex]
[tex]5x=80[/tex]
Divide both sides by 5.
[tex]x=\dfrac{80}{5}[/tex]
[tex]x=16[/tex]
Therefore, the required integer is 16 and your equation [tex]5-\dfrac{3}{4}x=5+\dfrac{1}{8}x[/tex] is incorrect.
