Answer:
The length of the image of the pole is 4/3 m
Explanation:
The given parameters are;
The length of the Pole = 4 m
The type of mirror = Convex mirror
The distance of the pole from the mirror = 2 m
The mirror formula for convex mirrors is presented here as follows;
[tex]\dfrac{1}{U} - \dfrac{1}{V} = - \dfrac{1}{F}[/tex]
Where;
U = The object (pole) distance from the mirror = 2 m
V = The image of the objects (pole) distance from the mirror
The focal length of the mirror
Therefore, by substitution, we have;
[tex]\dfrac{1}{2} - \dfrac{1}{V} = - \dfrac{1}{1}[/tex]
[tex]\dfrac{1}{2} + 1 = \dfrac{1}{V}[/tex]
[tex]\dfrac{1}{V} = \dfrac{1}{2} + 1 = \dfrac{3}{2}[/tex]
[tex]V = \dfrac{2}{3}[/tex]
We have;
[tex]Magnification = \dfrac{Image \ height}{Object \ height } = \dfrac{Length \ of \ the \ Image \ of \ the \ Pole}{Length \ of \ the \ of \ the \ Pole } =\dfrac{-V}{U}[/tex]
Which by substitution gives;
[tex]Magnification = \dfrac{Length \ of \ the \ Image \ of \ the \ Pole}{4} =\dfrac{-\dfrac{2}{3} }{2} = \dfrac{2}{6}[/tex]
[tex]{Length \ of \ the \ Image \ of \ the \ Pole}{} = 4 \times \dfrac{2}{6} = \dfrac{4}{3}[/tex]
The length of the image of the pole = 4/3 m
