Please solve this question..

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According to Thales theorem :
[tex] \frac{AB}{AE} = \frac{BC}{ED} \\ [/tex]
[tex] \frac{2}{2 + 5.2} = \frac{s}{6} \\ [/tex]
[tex] \frac{2}{7.2} = \frac{s}{6} \\ [/tex]
[tex] \frac{1}{3.6} = \frac{s}{6} \\ [/tex]
[tex] \frac{s}{6} = \frac{1}{3.6} \\ [/tex]
Multiply sides by 6
[tex]6 \times \frac{s}{6} = 6 \times \frac{1}{3.6} \\ [/tex]
Simplification
[tex]s = \frac{6}{3.6} \\ [/tex]
[tex]s = \frac{6}{36 \times {10}^{ - 1} } \\ [/tex]
[tex]s = \frac{6 \times {10}^{1} }{36} \\ [/tex]
[tex]s = \frac{6 \times 2 \times 5}{6 \times 2 \times 3} \\ [/tex]
6 s and 2 s are simplify
[tex]s = \frac{5}{3} \\ [/tex]
[tex]s≈1.67[/tex]
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