Answer:
see explanation
Step-by-step explanation:
Given a line CD parallel to a side of the triangle and intersecting the other 2 sides, then it divides those sides proportionally, thus
(a)
[tex]\frac{EC}{CA}[/tex] = [tex]\frac{ED}{DB}[/tex]
(b)
[tex]\frac{EC}{EA}[/tex] = [tex]\frac{ED}{EB}[/tex]
(c)
[tex]\frac{EB}{ED}[/tex] = [tex]\frac{EA}{EC}[/tex]
(d)
[tex]\frac{DB}{EB}[/tex] = [tex]\frac{CA}{EA\\}[/tex]
