Answer:
$30
Explanation:
Given that,
Power of a water heater, P = 2000 Watts
It is on for a total of 150 hours a month.
2000 Watts = 2 kW
Time, t = 150 hours
Energy used by the water heater is given by :
[tex]E=P\times t\\\\E=2\ kW\times 150\ h\\\\E=300\ kWh[/tex]
It is also mentioned that the cost is 10 cents per kWhr.
Since, $1 = 100 cents
10 cents = $0.1
So, the total cost for the month is :
Cost = 300 × 0.1
Cost = $30
So, the required cost is $30.
