The value of function g(2) is 1. Therefore, option A is the correct answer.
The given function is g(x)=[tex]\left \{ {{(\frac{1}{2} )^{x-3} \hspace{6em} x < 2} \atop {{x^{3}-9x^{2} +27x-25} } \hspace{6em}x \geq2}} \right.[/tex].
We need to find the value of g(2).
What is the function?
In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.
Now, g(2)= [tex](\frac{1}{2} )^{x-3} =2[/tex]
g(2)=2³-9(2)²+27×2-25
=8-36+54-25=1
The value of function g(2) is 1. Therefore, option A is the correct answer.
To learn more about the functions visit:
https://brainly.com/question/12431044.
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