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please help. I don't understand this. 50PTS

Function A(e) represents the surface area of a cube in terms of its edge length, e, and the difference quotient is 12e + 6h. What is the average rate of change in surface area of a cube as the edge length increases from 3 inches to 5 inches?

48 square inches per inch
54 square inches per inch
66 square inches per inch
96 square inches per inch

please help I dont understand this 50PTS Function Ae represents the surface area of a cube in terms of its edge length e and the difference quotient is 12e 6h W class=

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MathPhys

Answer:

48 square inches per inch

Step-by-step explanation:

The difference quotient is the average rate of change:

m = ΔA / Δe

m = (A(e+h) − A(e)) / h

m = 12e + 6h

In this case, e = 3 and h = Δe = 5−3 = 2.

m = 12(3) + 6(2)

m = 36 + 12

m = 48

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