Given:
The base area of a right circular cone is [tex]\dfrac{1}{4}[/tex] of its total surface area.
To find:
The ratio of the radius to the slant height.
Solution:
We know that,
Area of base of a right circular cone = [tex]\pi r^2[/tex]
Total surface area of a right circular cone = [tex]\pi rl+\pi r^2[/tex]
where, r is radius and l is slant height.
According to the question,
[tex]\pi r^2=\dfrac{1}{4}(\pi rl+\pi r^2)[/tex]
Multiply both sides by.
[tex]4\pi r^2=\pi rl+\pi r^2[/tex]
[tex]4\pi r^2-\pi r^2=\pi rl[/tex]
[tex]3\pi r^2=\pi rl[/tex]
Cancel out the common factors from both sides.
[tex]3r=l[/tex]
Now, ratio of the radius to the slant height is
[tex]\dfrac{r}{l}=\dfrac{r}{3r}[/tex]
[tex]\dfrac{r}{l}=\dfrac{1}{3}[/tex]
Therefore, the ratio of the radius to the slant height is 1:3.
