Two men pull a 31-kg box with forces 9.7 N and 7.6N in the directions shown below. Find the resultant acceleration of the box and the direction in which the box moves.

Respuesta :

Answer:

[tex]a=0.067\ m/s^2[/tex]

Explanation:

Given that,

Mass of the box, m = 31 kg

The two forces are shown in the attached figure. They are acting in opposite direction.

Net force, F = 9.7 - 7.6 = 2.1 N

The formula for net force is given by :

F = ma

a is resultant acceleration

[tex]a=\dfrac{F}{m}\\\\a=\dfrac{2.1}{31}\\\\a=0.067\ m/s^2[/tex]

So, the resultant acceleration is [tex]0.067\ m/s^2[/tex].

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