Answer:
33.26 m/s
Explanation:
The initial velocity of the ball can be determined by;
R = v[tex]\sqrt{\frac{2H}{g} }[/tex]
Where R is the range (distance between pitcher and catcher), H is the height covered, v is the initial velocity and g is the acceleration due gravity (9.8 m/[tex]s^{2}[/tex]).
So that;
18.4 = v[tex]\sqrt{\frac{2*1.5}{9.8} }[/tex]
= v [tex]\sqrt{\frac{3}{9.8} }[/tex]
= v [tex]\sqrt{0.3061}[/tex]
= 0.5533v
⇒ v = [tex]\frac{18.4}{0.5533}[/tex]
= 33.2550
The initial velocity of the ball is 33.26 m/s.This is the velocity with which the pitcher threw the ball.
