Answer:
Four times
Explanation:
The electrostatic force between the two charges is given by :
[tex]F=\dfrac{kq_1q_2}{d^2}[/tex]
d is the distance between two charges
k is electrostatic constant
When both charges are doubled, [tex]q_1'=2q_1\ \text{and}\ q_2'=2q_2[/tex], new force is given by :
[tex]F'=\dfrac{kq_1'q_2'}{d^2}\\\\F'=\dfrac{k(2q_1)(2q_2)}{d^2}\\\\F'=4\times \dfrac{kq_1q_2}{d^2}\\\\F'=4F[/tex]
So, the electrostatic force between them will be four times what it was before.
