Respuesta :

ZJSG09112007

Answer:

[tex]3\sqrt{2}[/tex]

Step-by-step explanation:

[tex]\sqrt{3} \times \sqrt{6}\\\\\mathrm{Factor\:integer\:}6=3\times\:2\\=\sqrt{3}\times\sqrt{3\times\:2}\\\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}\\\\\sqrt{3\times\:2}=\sqrt{3}\times\sqrt{2}\\\\=\sqrt{3}\times\sqrt{3}\times\sqrt{2}\\\\\mathrm{Apply\:radical\:rule}:\\\quad \sqrt{a}\times\sqrt{a}=a\\\\\sqrt{3}\times\sqrt{3}=3\\\\=3\sqrt{2}[/tex]

jxox

Answer:

3√2

Step-by-step explanation:

√3x6 = √18

√18 = √9x2 (√9 and √2)

√9 = 3

√2 = stays as root 2 as you cannot square root 2.

Therefore, answer is 3√2.

Hope this helps! :)

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