Answer:
y=12x+26
Step-by-step explanation:
We need an equation that passes through (-2,2) and is parallel to y-8=12x.
For this problem, we are going to use point slope form. Point slope form is written like this: [tex]y-y_{1} =m(x-x_{1})[/tex]. Parallel lines on graphs also have the same slope and different y-intercepts. Let's start plugging our known values. We will start with the slope. We know that the slope is 12, so m=12.
[tex]y-y_{1}=12(x-x_{1})[/tex].
We also know that [tex]y_{1} =2, x_{1}=-2[/tex]. Now let's solve
[tex]y-2=12(x+2)\\y-2=12x+24\\y=12x+26[/tex]
