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A wagon, initially traveling at a constant 8.5 m/s, starts going down a hill that creates an
acceleration of 4.1 m/s2. How far downhill has the wagon gone after 2.7 s ?

Respuesta :

quasarJose

Answer:

Explanation:

Given parameters:

Initial velocity  = 8.5m/s

Acceleration  = 4.1m/s²

Time  = 2.7s

Unknown:

Distance downhill traveled  = ?

Solution:

To solve this problem, we have to adopt the right motion equation;

          S = ut + [tex]\frac{1}{2}[/tex]at²

where  s = distance

            u = initial velocity

            a = acceleration

            t = time taken

Insert the parameters and solve;

  S = (8.5 x 2.7) + ([tex]\frac{1}{2}[/tex] x 4.1 x 2.7²)

  S = 22.95 + 14.95

  S = 37.9m

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