Answer:
"Both kinetic energy and angular moment of the system" is the correct solution.
Explanation:
The kinetic energy is:
[tex]KE=\frac{1}{2}m_{1}v_{1}^2 + \frac{1}{2}m_{2}v_{2}^2[/tex]
Its conversion is:
⇒ [tex](KE)_{1}=(KE)_{f}[/tex]
Angular momentum is:
[tex]L=I_{1}\omega_{1}+I_{2}\omega_{2}[/tex]
Its conversion is:
⇒ [tex]L_{i}=L_{f}[/tex]
So that both "KE" and "L" of the system conserved.