Given that,
Initial speed of a cat is 0 because it was at rest.
If it takes 1.2 s for the flowerpot to fall from the window, we need to find the height reached by the cat.
Using second equation of motion to find it as follows :
[tex]d=ut+\dfrac{1}{2}at^2[/tex]
Put u = 0 and a = g
[tex]d=\dfrac{1}{2}gt^2\\\\d=\dfrac{1}{2}\times 9.8\times (1.2)^2\\\\d=7.05\ m[/tex]
So, it will move to a height of 7.05 m.
