Answer:
400 V
Explanation:
The following data were obtained from the question:
Current in secondary coil (Iₛ) = 1 A
Current in primary coil (Iₚ) = 0.5 A
Emf in secondary coil (Eₛ) = 200 V
Emf in primary coil (Eₚ) =.?
The voltage (i.e emf) in the primary coil can be obtained as illustrated below:
Eₛ / Eₚ = Iₚ / Iₛ
200/Eₚ = 0.5/1
Cross multiply
Eₚ × 0.5 = 200 × 1
Eₚ × 0.5 = 200
Divide both side by 0.5
Eₚ = 200/0.5
Eₚ = 400 V
Therefore, the voltage in the primary coil is 400 V
