Respuesta :
Answer:
1.111 second
Explanation:
We know propagation speed = [tex]$2 \times 10^8$[/tex] m/s
= [tex]$2 \times 10^5$[/tex] km/s
One packet size = 1000 bit
Distance between sender and the receiver = 1000 m = 1 km
The channel data rate = 1 Mbps = [tex]$1 \times 10^6$[/tex] bits per sec
There is no transmission delays of ACKs,
The time to transmit one data packet = [tex]$T_{trans}+2T_{prop}$[/tex]
Here, time to transmit frame = [tex]$T_{trans}$[/tex]
propagation time = [tex]$T_{prop}$[/tex]
Therefore, [tex]$T_{trans}$[/tex] = [tex]$\frac{bits\ per\ frame}{transmission \ speed}$[/tex]
= [tex]$\frac{1000}{1 \times 10^6}$[/tex] = 0.001 seconds
[tex]$T_{prop}=\frac{distance\ between\ sender\ and\ receiver}{propagation \ speed}$[/tex]
= [tex]$\frac{1}{2 \times 10^5}$[/tex]
= 0.000005 seconds
Therefore, T = 0.001 +2(0.000005)
= 0.00101 seconds
We known, 1.1 million bits= 1100 packets
Therefore to transmit 1 million bits = 1100 x 0.00101
= 1.111 second
